Using return in shorthand if statement doesn't work

Question

I can't seem to understand why does this work:

if(n < i)
{
    functoin();
}
else
{
    return;
}

While this doesn't work:

(n < i) ? function() : return;

why does the shorthand if-statement doesn't work?

Answer 1

return can't be used in an expression. Maybe you can try,

return (n < i) ? function() : undefined;

But that's only if you have one thing to do for each condition.