如何从每个具有匹配文本的文件中删除行？

Question

$ grep "console.log" * -R
account/db.js:        console.log(err);
account/db.js:        console.log(info);
account/db.js:                console.log(err);
account/db.js:                    console.log(err2);
account/controller.js:    console.log(covers);
account/controller.js:    console.log(req.api_user);
account/controller.js:    console.log(code);
account/controller.js:        console.log(user);
account/helper.js:                console.log(err);
messages/db.js:        console.log("Error " + err);
messages/helper.js:                console.log('No email notify.');
messages/helper.js:                console.log(msg_body);
messages/helper.js:                        console.log(message.sid);
messages/helper.js:                        console.log(message.dateCreated);
messages/helper.js:                        console.log(error);
products/controller.js:            console.log(product);
products/controller.js:                console.log(product);
products/helper.js:        console.log(data)
products/helper.js:    console.log('removing index....');
profile/db.js:                console.log(err);
profile/db.js:                console.log(info);
profile/db.js:                console.log(err);
profile/controller.js:                            console.log("sending phone confirmation text...");
profile/helper.js:            console.log(message.sid);
profile/helper.js:            console.log(message.dateCreated);
profile/helper.js:            console.log(error);
receiver/controller.js:    console.log(from);
receiver/controller.js:    console.log(body);
receiver/controller.js:        console.log(from_email);
receiver/controller.js:        console.log(to_id_gen);
receiver/controller.js:        console.log(finalbody);
receiver/controller.js:                            console.log(result);
reviews/db.js:        console.log(err);
reviews/db.js:        console.log(results);
reviews/controller.js:            console.log(review);
reviews/controller.js:    console.log(review_id);
search/controller.js:        console.log(JSON.stringify(data.hits.hits, null, 4));

As you can see, while I was writing my code, I was doing console.log everywhere.

Now, I want to remove all those lines. I don't want to manually go into every file to remove them. Instead, I want to do it via a command.

Similar to grep "console.log" * -R , how can I do that same thing but remove those lines recursively? (look through every file all the way down the tree from my current directory)

Answer 1

try find for such things. try find . -type f -exec sed -i '/console\\.log/d' {} \\; find . -type f -exec sed -i '/console\\.log/d' {} \\; but you might be interested in using -i.bak instead of -i which keeps a back up copy

Answer 2

Give this a shot.

sed -i.bak '/console.log/d' */*.js

The -i param edits files in place. The original file will have .bak appended to its name, so you can restore it if something goes wrong, or you change your mind.

This is not a properly recursive solution; you may need to modify the file name wildcard, or drive the command from a find . -exec ... find . -exec ... wrapper to make it recursive.

Answer 3

在Perl中：

perl -i -n -e'print unless /console\.log/' $(find . -name '*.js')