如何从匹配行之后删除文件中的所有行？

Question

I have a file which is made up of several lines of text:

The first line
The second line
The third line
The fourth line

I have a string which is one of the lines: The second line

I want to delete the string and all lines after it in the file, so it will delete The third line and The fourth line in addition to the string. The file would become:

The first line

I've searched for a solution on google, and it seems that I should use sed . Something like:

sed 'linenum,$d' file

But how to find the line number of the string? Or, how else should I do it?

Answer 1

If you don't want to print the matched line (or any following lines):

sed -n '/The second line/q;p' inputfile

This says "when you reach the line that matches the pattern quit, otherwise print each line". The -n option prevents implicit printing and the p command is required to explicitly print lines.

or

sed '/The second line/,$d' inputfile

This says "delete all lines from the output starting at the matched line and continuing to the end of the file".

but the first one is faster. However it will quit processing completely so if you have multiple files as arguments, the ones after the first matching file won't be processed. In this case, the delete form is better.

If you do want to print the matched line, but not any following lines:

sed '/The second line/q' inputfile

This says "print all lines and quit when the matched line is reached" (the -n option (no implicit print) is not used).

See man sed for additional information.

Answer 2

This is a bit shorter than other given solutions. Quit using capital Q avoids printing the current line.

 sed '/The second line/Q' file

To actually delete the lines you can use the same syntax.

 sed -i '/The second line/Q' file

Answer 3

sed '/The second line/q0' file

Or, without gnu sed:

sed '/The second line/q' file

Or, using grep:

grep -B 9999999 "The second line"

Answer 4

使用awk（不显示匹配的行）

awk '/pattern/ {exit} {print}' file.txt

Answer 5

First add the line number and delete the line

cat new.txt 
The first line
The second line
The third line
The fourth line

 cat new.txt  | nl
     1  The first line
     2  The second line
     3  The third line
     4  The fourth line



cat new.txt  | nl | sed  "/2/d"
     1  The first line
     3  The third line
     4  The fourth line

cat new.txt  |  nl |sed  "3d;4d"
     1  The first line
     2  The second line

using awk

awk 'NR!=3 && NR!=4' new.txt 
The first line
The second line

Answer 6

awk '/The second line/{exit}1' file