RegExp用于从括号侧面移除空白区域

Question

I am stuck at creating a pattern to removes all white space after [ and before ]

replacement should produce:

--> [  tag content ] ---> [tag content]

Can somebody please help me write this regular expression

Answer 1

You could:

str = str.replace(/\[\s*(.*?)\s*]/g, '[$1]');

or

str = str.replace(/\[\s*/g, '[').replace(/\s*]/g, ']');

Answer 2

这应该可以帮助您：

str = str.replace(/(\[)\s+|\s+(])/g, '$1$2');

Answer 3

也试试这个：

a.replace(/\s*(\w+\s+\w+)\s*/g,"$1");