使用Python修改collections.Counter的输出

Question

I'm using the Python collections library to print out the most common character in a string and how many times it's repeated.

import collections
results = collections.Counter("this is fun")
listresults= results.most_common()
print listresults

this is what my result is :

[(' ', 2), ('i', 2), ('s', 2), ('f', 1), ('h', 1), ('n', 1), ('u', 1), ('t', 1)]

which is not what I want. I want something like

[(2,"i") (2, " "),...]

does anyone know how to produce the desired result?

Answer 1

You could try this:

>>> from collections import Counter
>>> results = Counter("this is fun")
>>> r = results.most_common()
>>> what_i_want = [(y, x) for x, y in r]
>>> what_i_want
[(2, ' '), (2, 'i'), (2, 's'), (1, 'f'), (1, 'h'), (1, 'n'), (1, 'u'), (1, 't')]

I use a list comprehension because list comprehensions are often more efficient than using for clauses and take up far less space. Per your comment below, though, a for clause would look like what jamylak has suggested:

>>> what_i_want = []
>>> for x, y in r:
    what_i_want.append((y, x))
>>> what_i_want
[(2, ' '), (2, 'i'), (2, 's'), (1, 'f'), (1, 'h'), (1, 'n'), (1, 'u'), (1, 't')]

Answer 2

Another slightly less readable but still quite pythonic way:

import collections
results = collections.Counter("this is fun")
listresults= results.most_common()
print listresults
print zip(*reversed(zip(*listresults)))