如何基于嵌套的for循环创建多个词典？

Question

Here is the output I am wanting:

level1 = {'value1':0, 'value2':0, 'value3':0}
level2 = {'value1':0, 'value2':0, 'value3':0}
level3 = {'value1':0, 'value2':0, 'value3':0}
level3 = {'value1':0, 'value2':0, 'value3':0}

Note: Value1, Value2, and Value3 are all the same thing. I am using this to just populate the dictionaries.

Here is what I am trying:

for x in range (1,6):
    level = 'level%d' % x
    for iteration in range(1, 4):
        value = 'value%d' % iteration
    level = {}
        level['value'] = 0

Answer 1

Are you trying something like this?:

dic={}
for x in range (1,6):
    level = 'level%d' % x 
    dic[level] = {}
    for iteration in range(1, 4): 
        value = 'value%d' % iteration
        dic[level][value] = 0 

print dic 

Output:

{'level1': {'value1': 0, 'value2': 0, 'value3': 0},
 'level2': {'value1': 0, 'value2': 0, 'value3': 0},
 'level3': {'value1': 0, 'value2': 0, 'value3': 0},
 'level4': {'value1': 0, 'value2': 0, 'value3': 0},
 'level5': {'value1': 0, 'value2': 0, 'value3': 0}}

Answer 2

So you want something like:

keys = ('value1','value2','value3')
{k:dict.fromkeys(keys,0) for k in range(1,4)}

demo:

>>> keys = ('value1','value2','value3')
>>> {k:dict.fromkeys(keys,0) for k in range(1,4)}
{1: {'value3': 0, 'value2': 0, 'value1': 0}, 2: {'value3': 0, 'value2': 0, 'value1': 0}, 3: {'value3': 0, 'value2': 0, 'value1': 0}}

Of course, with sequential integers as keys, you might consider indexing from 0 and using a list comprehension instead:

[dict.fromkeys(keys,0) for _ in range(3)]

Answer 3

You can nest the for loops in a nested dictionary comprehension and create a two-level nested dictionary like this:

from pprint import pprint

nested_dict = {'level%d' % level:
                    {'value%d' % value: 0 for value in range(1, 4)}
                                                 for level in range(1, 6)}
pprint(nested_dict)

Output:

{'level1': {'value1': 0, 'value2': 0, 'value3': 0},
 'level2': {'value1': 0, 'value2': 0, 'value3': 0},
 'level3': {'value1': 0, 'value2': 0, 'value3': 0},
 'level4': {'value1': 0, 'value2': 0, 'value3': 0},
 'level5': {'value1': 0, 'value2': 0, 'value3': 0}}