Here is the output I am wanting:
level1 = {'value1':0, 'value2':0, 'value3':0}
level2 = {'value1':0, 'value2':0, 'value3':0}
level3 = {'value1':0, 'value2':0, 'value3':0}
level3 = {'value1':0, 'value2':0, 'value3':0}
Note: Value1, Value2, and Value3 are all the same thing. I am using this to just populate the dictionaries.
Here is what I am trying:
for x in range (1,6):
level = 'level%d' % x
for iteration in range(1, 4):
value = 'value%d' % iteration
level = {}
level['value'] = 0
Are you trying something like this?:
dic={}
for x in range (1,6):
level = 'level%d' % x
dic[level] = {}
for iteration in range(1, 4):
value = 'value%d' % iteration
dic[level][value] = 0
print dic
Output:
{'level1': {'value1': 0, 'value2': 0, 'value3': 0},
'level2': {'value1': 0, 'value2': 0, 'value3': 0},
'level3': {'value1': 0, 'value2': 0, 'value3': 0},
'level4': {'value1': 0, 'value2': 0, 'value3': 0},
'level5': {'value1': 0, 'value2': 0, 'value3': 0}}
So you want something like:
keys = ('value1','value2','value3')
{k:dict.fromkeys(keys,0) for k in range(1,4)}
demo:
>>> keys = ('value1','value2','value3')
>>> {k:dict.fromkeys(keys,0) for k in range(1,4)}
{1: {'value3': 0, 'value2': 0, 'value1': 0}, 2: {'value3': 0, 'value2': 0, 'value1': 0}, 3: {'value3': 0, 'value2': 0, 'value1': 0}}
Of course, with sequential integers as keys, you might consider indexing from 0 and using a list comprehension instead:
[dict.fromkeys(keys,0) for _ in range(3)]
You can nest the for
loops in a nested dictionary comprehension and create a two-level nested dictionary like this:
from pprint import pprint
nested_dict = {'level%d' % level:
{'value%d' % value: 0 for value in range(1, 4)}
for level in range(1, 6)}
pprint(nested_dict)
Output:
{'level1': {'value1': 0, 'value2': 0, 'value3': 0},
'level2': {'value1': 0, 'value2': 0, 'value3': 0},
'level3': {'value1': 0, 'value2': 0, 'value3': 0},
'level4': {'value1': 0, 'value2': 0, 'value3': 0},
'level5': {'value1': 0, 'value2': 0, 'value3': 0}}
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