PHP / html / mysql图像显示

Question

Hey my php/mysql/html people,

I have this variable that holds a path to an image and then insert it into a db (yes, I am using mysql_real_escape_string) which works perfectly.

$file_name = $_FILES["file"]["name"];
$path='images\ '. $file_name;
insert into...blah blah blah

The path is later pulled from the db and stored in said variable.

$path       = $row['file_path'];

I am trying to display it with:

 // the contents of $path in this case is: images\ cats.jpg
echo "<img src=" . $path . ">";

However the image breaks because the only thing that src pics up is: images\\ and not the actualname+extension of the image. I know this probably has to do with the slashes, but I am a newbie and could use some help. Thanks in advance!

Answer 1

your

$path='images\ '. $file_name; 

should be

$path='images\'. $file_name;

Answer 2

Print $path variable & see the values.

echo $path;exit;

You will get value on web browser.

Copy the value displayed on browser & paste it in the URL, if you see the image, your saved path is correct, if not, you have gone wrong in specifying the relative path too the resource.