JQuery错误的ajax完成了回调

Question

I have a strange situation going on with ajax callbacks.

Call A works fine (I can see the server calls in the right place), and the done callback is fired correctly.

Call B call works fine (I can see the server calls in the right place), but then A's done callback is fired!

Here's the code: A:

$(document).ready(function () {
    $('#beta_signup_form').submit(function() {
        var valuesToSubmit = $(this).serialize();
        $.ajax({
            url: $(this).attr('action'), //submits it to the given url of the form
            data: valuesToSubmit,
            dataType: "JSON", // you want a difference between normal and ajax-calls, and json is standard
            type: 'POST'
        }).done(function(json){
            console.log("in the beta signup form success function!!!!");
        })
        .fail(function () {
            console.log("--------> beta signup modal callback error");
        });
        return false; // prevents normal behaviour
    });
});

and code B:

$(document).ready(function () {
    $('#twitter_sign_up').submit(function() {
        var valuesToSubmit = $(this).serialize();
        $.ajax({
            url: $(this).attr('action'), //submits it to the given url of the form
            data: valuesToSubmit,
            dataType: "JSON", // you want a difference between normal and ajax-calls, and json is standard
            type: 'POST'
        }).done(function(json) {
             console.log("in success for modal B...");
        }).fail(function () {
            console.log("--------> modal B callback error");
        });
        return false; // prevents normal behaviour
    });
});

What's going on here???

Answer 1

OH man... I just figured it out.

So I had:

<div id="twitter_sign_up">
  <form id="beta_signup_form" ...>
    ...
  </form>
</div>

My fault for copying html!