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jQuery $.ajax done 回调未触发

[英]jQuery $.ajax done callback not firing

I have the following code :我有以下代码:

$("#loginSubmitButton").on("click",function(){
  var loginUserDetails = {
    email: $("#email").val(),
    password: $("#password").val()
  };

  //Send the AJAX request to authenticate the user
  $.ajax({
    type: "POST",
    url: "/somewebservice/v1/users/authenticate",
    data: JSON.stringify(loginUserDetails),
    contentType: "application/json;charset=UTF-8",
    dataType: "json",
  }).done(function() {
      $("#loginResult").text("Login successful");
    })
    .fail(function() {
      $("#loginResult").text("Login failed");
    });

});

As per the jquery documentation (unless I am understanding something incorrectly) I expect the done to be fired if I receive a 200 OK from my web server.根据 jquery 文档(除非我理解错误),如果我从我的 Web 服务器收到 200 OK,我希望 done 被触发。 However, in chrome console I can see a 200 OK response but jquery seems to fire the fail handler.但是,在 chrome 控制台中,我可以看到 200 OK 响应,但 jquery 似乎触发了失败处理程序。

Does anyone have any idea what I might be doing wrong here?有谁知道我在这里可能做错了什么?

您需要删除:

dataType: "json"

There are lots of suggestions to remove有很多建议可以删除

dataType: "json"

While I grant that this works it's probably ignoring the underlying issue.虽然我承认这是有效的,但它可能忽略了潜在的问题。 It's most likely caused by a parser error (the browser parsing the json response).这很可能是由解析器错误(浏览器解析 json 响应)引起的。 Firstly examine the XHR parameter in either .always() or .fail().首先检查 .always() 或 .fail() 中的 XHR 参数。

Assuming it is a parser fail then why?假设它是一个解析器失败,那么为什么? Perhaps the return string isn't JSON.也许返回字符串不是 JSON。 Or it could be errant whitespace at the start of the response.或者它可能是响应开始时的错误空格。 Consider having a look at it in fiddler.考虑在 fiddler 中查看它。 Mine looked like this:我的看起来像这样:

Connection: Keep-Alive
Content-Type: application/json; charset=utf-8

{"type":"scan","data":{"image":".\/output\/ou...

In my case this was a problem with PHP spewing out unwanted characters (in this case UTF file BOMs).就我而言,这是 PHP 喷出不需要的字符(在这种情况下为 UTF 文件 BOM)的问题。 Once I removed these it fixed the problem while also keeping一旦我删除了这些,它就解决了问题,同时还保持

dataType: json

If your server returns empty string for a json response (even if with a 200 OK), jQuery treats it as failed.如果您的服务器为 json 响应返回空字符串(即使是 200 OK),jQuery 会将其视为失败。 Since v1.9, an empty string is considered invalid json.从 v1.9 开始,空字符串被认为是无效的 json。

Whatever is the cause, a good place to look at is the 'data' parameter passed to the callbacks:无论是什么原因,一个值得关注的地方是传递给回调的“数据”参数:

$.ajax( .. ).always(function(data) {
    console.log(JSON.stringify(data));
});

Its contents will give you an understanding of what's wrong.它的内容将使您了解问题所在。

需要删除 , from dataType: "json",

 dataType: "json"

The ajax URL must be the same domain. ajax URL 必须是同一个域。 You can't use AJAX to access cross-domain scripts.您不能使用 AJAX 访问跨域脚本。 This is because of the Same Origin Policy.这是因为同源策略。
add "dataType:JSONP" to achieve cross domain communication添加“dataType:JSONP”实现跨域通信

use below code使用下面的代码

 $.ajax({
       URL: cross domain 

        dataType: 'jsonp'  
            // must use dataType:JSONP to achieve cross domain communication, otherwise done function would not called. 
           // jquery ajax will return "statustext error" at }).always(function(data){}


 }).always(function(data){
      alert(JSON.stringify(data));
   }

A few things that should clear up your issue and a couple hints in general.一些应该可以解决您的问题的事情以及一些提示。

  1. Don't listen for a click on a submit button.不要听点击提交按钮。 You should wait for the submit event on the form.您应该等待表单上的提交事件。

  2. The data option for $.ajax isn't expecting a JSON string. $.ajaxdata选项不需要 JSON 字符串。 It wants a serialized string or an array with name and value objects.它需要一个序列化的字符串或一个带有名称和值对象的数组。 You can create either of those easily with .serialize() or .serializeArray() .您可以使用.serialize().serializeArray()轻松创建其中任何一个。

Here is what I was thinking for your script.这是我对你的脚本的想法。

$('#form-with-loginSubmitButton').on('submit', function(e){


  e.preventDefault():

  var $form = $(this),
      data = $form.serializeArray();

  $.ajax({
    type: "POST",
    url: "/somewebservice/v1/users/authenticate",
    data: data
  }).done(function(result){
    console.log(result);
  });

});

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