如何优化这个smoothstep函数？ 有什么替代方法吗？

Question

In one of my projects, I use the following smoothstep() function :

float smoothstep(float a, float b, float m, int n)
{
    for(int i = 0 ; i < n ; i++)
    {
        m = m * m * (3 - 2 * m);
    }
    return a + (b - a) * m;
}

It works great, however, it has two disadvantages :

• It's slow (especially for big values of n )
• It doesn't work for non integer values (eg : n = 1.5 )

Is there an alternative (excluding precalculating points and then interpolating) providing better performance (and same behavior), or another function giving a great approximation ?

Answer 1

You should be able to precompute the "m" term, since it doesn't rely on a or b, and assuming you're doing this over an entire interpolation, this should speed up your code significantly.

Alternatively, you could use the built in MathHelper.Smoothstep method, which provides a cubic interpolation, rather than the linear interpolation you get out of your version. There are also other, more advanced, interpolators in that class, also.