[英]How to replace a particular string with value in java
EDIT : 编辑:
Goal : http://localhost:8080/api/upload/form/test/test
目标:
http://localhost:8080/api/upload/form/test/test
Is it possible to have some thing like `{a-b, A-B..0-9}` kind of pattern and match them and replace with value.
i have following string 我有以下字符串
http://localhost:8080/api/upload/form/{uploadType}/{uploadName}
there can be any no of strings like {uploadType}/{uploadName}
. 不能有任何字符串,例如
{uploadType}/{uploadName}
。
how to replace them with some values in java? 如何用Java中的某些值替换它们?
[Edited] Apparently you don't know what substitutions you'll be looking for, or don't have a reasonable finite Map of them. [编辑]显然,您不知道要寻找什么替代品,或者没有合理的有限映射。 In this case:
在这种情况下:
Pattern SUBST_Patt = Pattern.compile("\\{(\\w+)\\}");
StringBuilder sb = new StringBuilder( template);
Matcher m = SUBST_Patt.matcher( sb);
int index = 0;
while (m.find( index)) {
String subst = m.group( 1);
index = m.start();
//
String replacement = "replacement"; // .. lookup Subst -> Replacement here
sb.replace( index, m.end(), replacement);
index = index + replacement.length();
}
Look, I'm really expecting a +1 now. 看,我真的很期待+1。
[Simpler approach] String.replace()
is a 'simple replace' & easy to use for your purposes; [更简单的方法]
String.replace()
是一个“简单替换”并且易于使用。 if you want regexes you can use String.replaceAll()
. 如果需要正则表达式,可以使用
String.replaceAll()
。
For multiple dynamic replacements: 对于多个动态替换:
public String substituteStr (String template, Map<String,String> substs) {
String result = template;
for (Map.Entry<String,String> subst : substs.entrySet()) {
String pattern = "{"+subst.getKey()+"}";
result = result.replace( pattern, subst.getValue());
}
return result;
}
That's the quick & easy approach, to start with. 首先,这是快速简便的方法。
You can use the replace method in the following way: 您可以通过以下方式使用replace方法:
String s = "http://localhost:8080/api/upload/form/{uploadType}/{uploadName}";
String typevalue = "typeValue";
String nameValue = "nameValue";
s = s.replace("{uploadType}",value).replace("{uploadName}",nameValue);
You can take the string that start from {uploadType} till the end. 您可以采用从{uploadType}到结尾的字符串。 Then you can split that string using "split" into string array.
然后,您可以使用“ split”将字符串拆分为字符串数组。 Were the first cell(0) is the type and 1 is the name.
第一个单元格(0)是类型,而1是名称。
String s = "http://localhost:8080/api/upload/form/{uploadType}/{uploadName}";
String result = s.replace("uploadType", "UploadedType").replace("uploadName","UploadedName");
EDIT: Try this: 编辑:试试这个:
String r = s.substring(0 , s.indexOf("{")) + "replacement";
Solution 1 : 解决方案1:
String uploadName = "xyz";
String url = "http://localhost:8080/api/upload/form/" + uploadName;
Solution 2: 解决方案2:
String uploadName = "xyz";
String url = "http://localhost:8080/api/upload/form/{uploadName}";
url.replace("{uploadName}",uploadName );
Solution 3: 解决方案3:
String uploadName = "xyz";
String url = String.format("http://localhost:8080/api/upload/form/ %s ", uploadName);
The UriBuilder
does exactly what you need: UriBuilder
完全UriBuilder
您的需求:
UriBuilder.fromPath("http://localhost:8080/api/upload/form/{uploadType}/{uploadName}").build("foo", "bar");
Results in: 结果是:
http://localhost:8080/api/upload/form/foo/bar
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