[英]find index of row matching a given criteria
I have the following list ( nodes
): 我有以下列表(
nodes
):
nodeID, x, y, z=row
I want to find the index of the row which row[0]==nodeAID
. 我想找到
row[0]==nodeAID
的行的索引。
My code is: 我的代码是:
nindF=[line[0].index(nodeAID) for line in nodes]
but it gives me the error: TypeError: expected a character buffer object
但它给了我错误:
TypeError: expected a character buffer object
nindF = [index for index, line in enumerate(nodes) if line[0].find(nodeAID) >= 0]
This will return a list of indexes of all the lines that start with nodeAID. 这将返回以nodeAID开头的所有行的索引列表。 If you only care about the index of the first line that starts with nodeAID then:
如果您只关心以nodeAID开头的第一行的索引,则:
nindF = [index for index, line in enumerate(nodes) if line[0].find(nodeAID) >= 0][0]
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