[英]Fetch images URL from XML
I am using the below code to fetch the $movie->id from the response XML 我使用以下代码从响应XML中获取$ movie-> id
<?php
$movie_name='Dabangg 2';
$url ='http://api.themoviedb.org/2.1/Movie.search/en/xml/accd3ddbbae37c0315fb5c8e19b815a5/%22Dabangg%202%22';
$xml = simplexml_load_file($url);
$movies = $xml->movies->movie;
foreach ($movies as $movie){
$arrMovie_id = $movie->id;
}
?> ?>
the response xml structure is 响应xml结构是
How to fetch image URL with thumb size? 如何用拇指大小获取图片网址?
Use the attributes() method of SimpleXmlElement. 使用SimpleXmlElement的attributes()方法。
Example: 例:
$imageAttributes = $movie->images[0]->attributes();
$size = $imageAttributes['size'];
See the documentation at: http://www.php.net/manual/en/simplexmlelement.attributes.php 请参阅以下文档: http : //www.php.net/manual/en/simplexmlelement.attributes.php
See the below an easy way to get only specific images. 请参阅下面一个简单的方法来获取特定图像。
$xml = simplexml_load_file($url);
$images = $xml->xpath("//image");
//echo "<pre>";print_r($images);die;
foreach ($images as $image){
if($image['size'] == "thumb"){
echo "URL:".$image['url']."<br/>";
echo "SIZE:".$image['size']."<br/>";
echo "<hr/>";
}
}
EDIT: select only URL
attributes with size = "thumb"
and type = "poster"
: 编辑:仅选择size = "thumb"
和type = "poster"
URL
属性:
$urls = $xml->xpath("//image[@size='thumb' and @type='poster']/@url");
if you expect only 1 url, do: 如果您只想要1个网址,请执行以下操作:
$url = (string)$xml->xpath("//image[@size='thumb' and @type='poster']/@url")[0];
echo $url;
working live demo: http://codepad.viper-7.com/wdmEay 现场演示演示: http : //codepad.viper-7.com/wdmEay
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