[英]Fetch images URL from XML
我使用以下代碼從響應XML中獲取$ movie-> id
<?php
$movie_name='Dabangg 2';
$url ='http://api.themoviedb.org/2.1/Movie.search/en/xml/accd3ddbbae37c0315fb5c8e19b815a5/%22Dabangg%202%22';
$xml = simplexml_load_file($url);
$movies = $xml->movies->movie;
foreach ($movies as $movie){
$arrMovie_id = $movie->id;
}
?>
響應xml結構是
如何用拇指大小獲取圖片網址?
使用SimpleXmlElement的attributes()方法。
例:
$imageAttributes = $movie->images[0]->attributes();
$size = $imageAttributes['size'];
請參閱以下文檔: http : //www.php.net/manual/en/simplexmlelement.attributes.php
請參閱下面一個簡單的方法來獲取特定圖像。
$xml = simplexml_load_file($url);
$images = $xml->xpath("//image");
//echo "<pre>";print_r($images);die;
foreach ($images as $image){
if($image['size'] == "thumb"){
echo "URL:".$image['url']."<br/>";
echo "SIZE:".$image['size']."<br/>";
echo "<hr/>";
}
}
編輯:僅選擇size = "thumb"
和type = "poster"
URL
屬性:
$urls = $xml->xpath("//image[@size='thumb' and @type='poster']/@url");
如果您只想要1個網址,請執行以下操作:
$url = (string)$xml->xpath("//image[@size='thumb' and @type='poster']/@url")[0];
echo $url;
現場演示演示: http : //codepad.viper-7.com/wdmEay
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.