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在mysql的一栏中选择多个具有相同值的行?

[英]Select more than one row with same value in one column in mysql?

I'm trying to make a comment system using PHP and MySQL. 我正在尝试使用PHP和MySQL创建注释系统。 I have made a table named "comment" which stores the details 我制作了一个名为“ comment”的表,用于存储详细信息

id  | date      |product_id | user_name | email_id          | comment
    |           |           |           |                   |
1   |2013-05-07 |  10001    |  jabong   | jabong@jabong.com | this is good product
2   |2013-05-07 |  10001    |  john     | john@gmail.com    | I bought this product

and so on 等等


Now I want to select and print all those rows which have product_id=10001. 现在,我要选择并打印所有具有product_id = 10001的行。 I'm using the following code to print the details 我正在使用以下代码来打印详细信息

  $comment="";
  $id=$_GET['id'];//this is the product_id which is taken from URL
  $query=mysql_query("SELECT * FROM comment WHERE product_id='$id'");
  while($data = mysql_fetch_array($query))
    {
        $name = $data["user_name"];
        $email = $data["email_id"];
        $comment = $data["comment"];
        $date=strftime("%d %b, %Y", strtotime($data["date"]));

        $comment.='<table>
                      <tr>
                        <td>Date: '.$date.'</td>
                      </tr>
                      <tr>
                        <td>Name: '.$name.'</td>
                      </tr>
                      <tr>
                        <td>Email_id: '.$email.'</td>
                      </tr>
                      <tr>
                        <td>Product Review: '.$comment.'</td>
                      </tr>
                    </table><hr />'; 

and then I'm echoing them in the body section. 然后在正文部分中回显它们。 but I'm getting only one result. 但我只得到一个结果。 so please help me to get the right code. 因此,请帮助我获取正确的代码。

There was a small problem with my code. 我的代码有一个小问题。 I was using the same variable twice and also i didn't use the concatenate symbol. 我两次使用相同的变量,也没有使用连接符号。 But now it is solved--- 但是现在解决了-

      $review="";
      if (isset($_GET['id']))
  {
      $id=mysql_real_escape_string(trim($_GET['id']));
      $query=mysql_query("SELECT * FROM comment WHERE product_id='$id'");
      $review.='<table width="70%" cellpadding="6px" cellspacing="0" >';
      while($data=mysql_fetch_array($query))
        {
            $name = $data["user_name"];
            $email = $data["email_id"];
            $comment = $data["comment"];
            $date=strftime("%d %b, %Y", strtotime($data["date"]));
            $review.='<tr>
                        <td>
                          <table width="100%" border="0" style="border:1px solid; border-color:#05fdee; background-color:#e4f2f1;">
                              <tr>
                                <td rowspan="2" width="100px"> <img src="profile.png" /> </td>
                                <td align="left"><b> '.$name.' </b> says -</td>
                                <td align="right"><b> '.$date.' </b></td>
                              </tr>
                              <tr>
                                <td colspan="2">'.$comment.'</td>
                              </tr>
                          </table>
                        </td>
                      </tr>';

        }// while loop ends here
        $review.='</table>'; 
  } 

First most important thing, clean your data. 首先,清理数据。

$id=mysql_real_escape_string(trim($_GET['id']));
$query=mysql_query("SELECT * FROM comment WHERE product_id='$id'");

while($data = mysql_fetch_array($query)) while($ data = mysql_fetch_array($ query))

The second problem is you are overwriting the variable $comment in each loop, so you are only getting 1 record, even though you are looping twice. 第二个问题是您在每个循环中都覆盖了$ comment变量,因此即使循环两次,您也只会得到1条记录。

remove this: $comment = $data["comment"];
change this: <td>Product Review: '.$comment.'</td>
to this: <td>Product Review: '.$data["comment"].'</td>

you have this line: 你有这行:

$comment = $data["comment"];

that's overwriting this one: 这覆盖了这个:

$comment.='<table>
                      <tr>
                        <td>Date: '.$date.'</td>
                      </tr>
                      <tr>
                        <td>Name: '.$name.'</td>
                      </tr>
                      <tr>
                        <td>Email_id: '.$email.'</td>
                      </tr>
                      <tr>
                        <td>Product Review: '.$comment.'</td>
                      </tr>
                    </table><hr />'; 

so when you're making the echo $comment it's displaying the last one. 因此,当您在执行echo $comment它会显示最后一个。

Change the variable and DONE 更改变量并完成

something like: 就像是:

 $comment_sql = $data["comment"];
....
    $comment.='<table>
                          <tr>
                            <td>Date: '.$date.'</td>
                          </tr>
                          <tr>
                            <td>Name: '.$name.'</td>
                          </tr>
                          <tr>
                            <td>Email_id: '.$email.'</td>
                          </tr>
                          <tr>
                            <td>Product Review: '.$comment_sql.'</td>
                          </tr>
                        </table><hr />'; 
...

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