从Python字符串中删除多种字符

Question

I have some string X and I wish to remove semicolons, periods, commas, colons, etc, all in one go. Is there a way to do this that doesn't require a big chain of .replace(somechar,"") calls?

Answer 1

You can use re.sub to pattern match and replace. The following replaces h and i only with empty strings:

In [1]: s = 'byehibyehbyei'

In [1]: re.sub('[hi]', '', s)
Out[1]: 'byebyebye'

Don't forget to import re .

Answer 2

>>> import re
>>> foo = "asdf;:,*_-"
>>> re.sub('[;:,*_-]', '', foo)
'asdf'

• [;:,*_-] - List of characters to be matched
• '' - Replace match with nothing
• Using the string foo .

For more information take a look at the re.sub(pattern, repl, string, count=0, flags=0) documentation .

Answer 3

You can use the translate method with a first argument of None :

string2 = string1.translate(None, ";.,:")

Alternatively, you can use the filter function :

string2 = filter(lambda x: x not in ";,.:", string1)

Note that both of these options only work for non-Unicode strings and only in Python 2.

Answer 4

Don't know about the speed, but here's another example without using re .

commas_and_stuff = ",+;:"
words = "words; and stuff!!!!"
cleaned_words = "".join(c for c in words if c not in commas_and_stuff)

Gives you:

'words and stuff!!!!'