[英]MongoDB count() distinct in php
I am wondering how to count the number of results of this simple mongodb query, using php. 我想知道如何使用PHP计算这个简单的mongodb查询的结果数。
<?php
//connection to mongodb
$collection = new MongoCollection($db, 'User');
$retval = $collection->distinct("age");
var_dump($retval);
?>
How can i count how many results are into $retval variable? 我如何计算$ retval变量中有多少结果?
Soory , to know how many result are in $retval its simple. Soory ,要知道在$ retval中有多少结果很简单。 Just write this:
写下这个:
echo count($retval);
My solution returns the count of child for one item distincted. 我的解决方案返回一个项目的子计数。 Not the count of simple distinct collection ^^
不是简单的不同集合的计数^^
For example if you have these data: 例如,如果您有这些数据:
Age: | User:
--------------
{ "age":"20", "name":"David" },
{ "age":"20", "name":"Goerge" },
{ "age":"22", "name":"tiffany" }
My solution return an array and when you each this array such as: 我的解决方案返回一个数组,当你每个这个数组,如:
foreach ($retval as $row)
echo($row['age'] . ': ' . $row['count'] . "\n");
Data returned: 返回的数据:
20 : 2
22 : 1
The new Aggregation framework is going to make this easy: http://php.net/manual/en/mongocollection.aggregate.php 新的Aggregation框架将使这一切变得简单: http : //php.net/manual/en/mongocollection.aggregate.php
$project = array('$project'=> array("age"=>1)); //pick only the age field
$group = array('$group'=>array("_id"=>'$age')); //group by age field
$count = array('$group'=>array("_id"=>null,"count"=>array('$sum'=>1))); //count distinct
$result = $collection->aggregate(array($project,$group,$count));
echo $result['result'][0]['count'];
The PHP documentation for MongoDB describe how count in a getting collection: http://www.php.net/manual/en/mongocollection.count.php MongoDB的PHP文档描述了获取集合的计数: http : //www.php.net/manual/en/mongocollection.count.php
For have the count over distinct result, you can create a map-reduce in group collecting such as this example: 为了计算不同的结果,您可以在组收集中创建map-reduce,例如:
<?php
$retval = $collection->group(
array('age' => true), // field(s) to group by
array('count' => 0),
new MongoCode('function(doc, prev) { prev.count += 1 }'),
array(null) // condition
);
?>
The 该
new MongoCode(..)
function takes the current document and the aggregation to this point and does the aggregation. function将当前文档和聚合带到此点并进行聚合。 And finaly you can get the count:
最后你可以得到数:
print($retval["count"]);
$collection = new MongoCollection($db, 'contacts');
$keys = array("Department" => 1);
// set intial values
$initial = array("count" => 0);
// JavaScript function to perform
$reduce = "function (obj, prev) { prev.count++; }";
// only use documents where the "state" field is ar
$condition = array('condition' => array("State" => 'AR'));
$results = $collection->group($keys, $initial, $reduce, $condition);
foreach ($results['retval'] as $key => $value) {
echo 'Contacts in state AR with department '.$value['Department'] . ' are:'. $value['count'];
echo '<br />';
}
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