PHP mongoDB的独特选择

Question

This is my first time posting here in stackoverflow. I am hoping someone can help me with my issue with mongoDB PHP. I am more of a PHP mySql guy but we suddenly needed to switch to mongoDB. Below is the problem situation in the most explanation that I can give.

Imagine in mysql, I have a table named "photos" with 3 fields (img_id, owner_id, and file_path). And with record below:

Record #1: 1---1---image01.jpg

Record #2: 2---2---image02.jpg

Record #3: 3---2---image03.jpg

Then I have another table named "users" with 2 fields (user_id, fullname) with records below:

Record #1: 1---Jhon Doe

Record #2: 2---Mark Kane

All I need is to display results similar to below:

1.) John Doe has 1 image and the image id is 1 . - image01.jpg

2.) Mark Kane has 2 images and the image ids are 2 and 3 . - image01.jpg, image02.jpg

Please let me know how this should be done in mongoDB PHP. Thanks in advance.

Answer 1

$m = new Mongo();
$collection = $m->users;
$collection1 = $m->photos;
$cursor = $collection->find();
$cursor1 = $collection1->find();

$count = 0;
$result = array();
$path = array();
$str = "";
$str1 = "";
foreach($cursor as $obj){
    foreach($cursor1 as $obj1){
        if($obj['user_id'] == $obj1['owner_id']){
            $result[$count] = $obj1['img_id'];
            $path[$count] = $obj1['file_path'];         
            $count++;
        } 
    }
    if($count > 1){
        for($i = 0; $i < $count; $i++){
            $str .= $result[$count]." and ";
            $str1 .= $path[$count]." , ";
        }       
    }
    else{   
        $str = $result[0];
        $str1 = $path[0];   
    }
    print "$obj['fullname'] has $count image and the image id is $str - $str1 .";
}

Hope the above code block gives you the desired result, the code is not tested, so some compiler or syntactical errors may be there, but I hope you can solve them.