[英]PostgreSQL: Call a Function More Than Once in FROM Clause
How can I call a function which returns records more than once in FROM clause? 如何在FROM子句中调用一个返回记录多次的函数? I understand that I have to specify a 'column definition list' when using a function that returns records.
我了解使用返回记录的函数时,必须指定“列定义列表”。 But how can I then use aliases for that function?
但是我该如何使用别名呢?
Example: 例:
CREATE OR REPLACE FUNCTION foo(which_foo int) RETURNS SETOF RECORD AS
$BODY$BEGIN
IF which_foo=0 THEN
RETURN QUERY EXECUTE 'SELECT 1::int,2::int;';
ELSE
RETURN QUERY EXECUTE 'SELECT 1::int,2::int;';
END IF;
END$BODY$
LANGUAGE plpgsql;
SELECT * FROM foo(0) AS (a int, b int);;
SELECT * FROM foo(1) AS (c int, d int);
SELECT * FROM foo(0) AS (a int, b int), foo(1) AS (c int, d int);
The last select statement will fail with: 最后一个选择语句将失败,并显示:
ERROR: table name "foo" specified more than once
I want to keep using the column definition list, because the function I want to use in the end has to be as generic as possible. 我想继续使用列定义列表,因为最后要使用的函数必须尽可能通用。
SELECT f0.*, f1.*
FROM
foo(0) AS f0 (a int, b int),
foo(1) AS f1 (c int, d int);
I understand that I have to specify a 'column definition list' when using a function that returns records.
我了解使用返回记录的函数时,必须指定“列定义列表”。
No, you do not. 你不可以。 I wouldn't operate with anonymous records.
我不会处理匿名记录。 Declare the return type , since you already know it:
声明返回类型 ,因为您已经知道它:
CREATE OR REPLACE FUNCTION foo(which_foo int)
RETURNS TABLE (a int, b int) AS
$func$
BEGIN
IF which_foo = 0 THEN
RETURN QUERY SELECT 1,2;
ELSE
RETURN QUERY SELECT 1,2;
END IF;
END
$func$ LANGUAGE plpgsql;
And assuming you do not want to combine multiple calls into one row, you should use UNION ALL
: 并假设您不想将多个调用合并为一行,则应使用
UNION ALL
:
SELECT * FROM foo(0)
UNION ALL
SELECT * FROM foo(1);
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