[英]Instantiate parameterized type using Class.forName
I have the following classes: 我有以下课程:
public class B {
}
public class A<B> {
}
How do I instantiate class A
using Class.forName
, given that I have two string variables: 如何使用
Class.forName
实例化A
类,因为我有两个字符串变量:
String classNameA = "A";
String classNameB = "B";
Due to type erasure , there won't be any generic classes at run time. 由于类型擦除 ,在运行时不会有任何泛型类。
For instance, the following piece of code will output class java.util.ArrayList
without generics: 例如,下面的代码将输出没有泛型的
class java.util.ArrayList
:
List<String> list = new ArrayList<String>();
System.out.println(list.getClass());
Class<B> bClass = (Class<B>) Class.forName(classNameB);
B b = bClass.newInstance();
Class<A<B>> aClass = (Class<A<B>>) Class.forName(classNameA);
A<B> a = aClass.newInstance();
The type parameter of type A does not exist during runtime, so you can cast aClass
to Class<A<B>>
. 类型A的类型参数在运行时期间不存在,因此您可以将
aClass
为Class<A<B>>
aClass
Class<A<B>>
。
Since all instances of a generic class share the same class object, the type parameter doesn't matter to the runtime, so you can simply do: 由于泛型类的所有实例共享同一个类对象,因此type参数对运行时无关紧要,因此您只需执行以下操作:
Class.forName("A").newInstance();
and cast the result to whatever type you need. 并将结果转换为您需要的任何类型。
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