我将如何制作它，以使此koch雪花中的每个新一代三角形都是不同的颜色？ （Python +龟）

Question

So I have this program that generates a hexagonal koch snowflake using these two main functions:

def mvmt(length):

if length <= 10:
    voldemort.forward(length)
else:
    mvmt(length/3)
    voldemort.right(60)
    mvmt(length/3)
    voldemort.left(120)
    mvmt(length/3)
    voldemort.right(60)
    mvmt(length/3)


def whole(length = 300):
    voldemort.hideturtle()
    voldemort.penup()
    voldemort.goto(-300,-255)
    voldemort.pendown()
    voldemort.begin_fill()
    mvmt(length)
    voldemort.left(60)
    mvmt(length)
    voldemort.left(60)
    mvmt(length)
    voldemort.left(60)
    mvmt(length)
    voldemort.left(60)
    mvmt(length)
    voldemort.left(60)
    mvmt(length)
    voldemort.end_fill() 

How do I make it so that each new set of triangles added through the iterative process is a new color?

I'd rather not use meticulous processes of changing the fill color, then running "voldemort.beginfill()" and "voldemort.endfill()". Help is highly appreciated. NOTE This is written in python using the Turtle Module.

Answer 1

One way to do it is to clone the turtle inside mvmt() , so you have an independent one that you can fill without interfering with the filling of the outer one.

To make that work recursively, you have to pass the current turtle as a parameter to mvmt() .

That's what I changed your code to:

#!/usr/bin/env python

from __future__ import division

import colorsys
import turtle

def mvmt(original, length):
    if length >= 10:
        fraction = length / 3
        h, s, v = colorsys.rgb_to_hsv(*original.fillcolor())

        clone = original.clone()
        clone.fillcolor(colorsys.hsv_to_rgb(h + 1/6, s, v))
        clone.begin_fill()
        mvmt(clone, fraction)
        clone.right(60)
        mvmt(clone, fraction)
        clone.left(120)
        mvmt(clone, fraction)
        clone.right(60)
        mvmt(clone, fraction)
        clone.end_fill()

    original.forward(length)

def whole(length = 300):
    voldemort = turtle.Turtle()
    voldemort.speed(0)
    voldemort.hideturtle()
    voldemort.penup()
    voldemort.goto(-200,-255)
    voldemort.pendown()

    voldemort.fillcolor((1.0, 0.5, 0.5))
    voldemort.begin_fill()
    mvmt(voldemort, length)
    voldemort.left(60)
    mvmt(voldemort, length)
    voldemort.left(60)
    mvmt(voldemort, length)
    voldemort.left(60)
    mvmt(voldemort, length)
    voldemort.left(60)
    mvmt(voldemort, length)
    voldemort.left(60)
    mvmt(voldemort, length)
    voldemort.end_fill()

turtle.delay(0)
turtle.speed(0)

whole()
turtle.exitonclick()