![](/img/trans.png)
[英]Koch snowflake rendering time (and how to draw a snowflake using turtle)
[英]How would I go about making it so that each new generation of triangles in this koch snowflake is a different color? (Python + Turtle)
因此,我有一個使用以下兩個主要功能生成六角形科赫雪花的程序:
def mvmt(length):
if length <= 10:
voldemort.forward(length)
else:
mvmt(length/3)
voldemort.right(60)
mvmt(length/3)
voldemort.left(120)
mvmt(length/3)
voldemort.right(60)
mvmt(length/3)
def whole(length = 300):
voldemort.hideturtle()
voldemort.penup()
voldemort.goto(-300,-255)
voldemort.pendown()
voldemort.begin_fill()
mvmt(length)
voldemort.left(60)
mvmt(length)
voldemort.left(60)
mvmt(length)
voldemort.left(60)
mvmt(length)
voldemort.left(60)
mvmt(length)
voldemort.left(60)
mvmt(length)
voldemort.end_fill()
我如何使通過迭代過程添加的每組新三角形都是一種新顏色?
我寧願不使用更改填充顏色的細致過程,然后運行“ voldemort.beginfill()”和“ voldemort.endfill()”。 非常感謝您的幫助。 注意這是使用Turtle模塊以python編寫的。
一種方法是在mvmt()
克隆烏龜,這樣您就可以獨立填充一個烏龜,而不會干擾外部的填充。
為了使該遞歸工作,您必須將當前的turtle作為參數傳遞給mvmt()
。
那就是我將您的代碼更改為:
#!/usr/bin/env python
from __future__ import division
import colorsys
import turtle
def mvmt(original, length):
if length >= 10:
fraction = length / 3
h, s, v = colorsys.rgb_to_hsv(*original.fillcolor())
clone = original.clone()
clone.fillcolor(colorsys.hsv_to_rgb(h + 1/6, s, v))
clone.begin_fill()
mvmt(clone, fraction)
clone.right(60)
mvmt(clone, fraction)
clone.left(120)
mvmt(clone, fraction)
clone.right(60)
mvmt(clone, fraction)
clone.end_fill()
original.forward(length)
def whole(length = 300):
voldemort = turtle.Turtle()
voldemort.speed(0)
voldemort.hideturtle()
voldemort.penup()
voldemort.goto(-200,-255)
voldemort.pendown()
voldemort.fillcolor((1.0, 0.5, 0.5))
voldemort.begin_fill()
mvmt(voldemort, length)
voldemort.left(60)
mvmt(voldemort, length)
voldemort.left(60)
mvmt(voldemort, length)
voldemort.left(60)
mvmt(voldemort, length)
voldemort.left(60)
mvmt(voldemort, length)
voldemort.left(60)
mvmt(voldemort, length)
voldemort.end_fill()
turtle.delay(0)
turtle.speed(0)
whole()
turtle.exitonclick()
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.