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cout打印字符串变量无法通过构建

[英]cout print string variable cannot pass the build

Could any one help me to figure out which the following code cannot build successfully: 谁能帮助我找出以下代码无法成功构建的地方:

#include <iostream>

int main(void){

    std::string str1("sfsfasfdsdf");
    std::cout << str1 << std::endl;
    return 1;
}

Thanks. 谢谢。

You have to include std::string header: 您必须包括std::string标头:

#include <string>

EDIT : According to @ShafikYaghmour's comments, include iostream sometimes brings in string , but it may not be the case for you if you only have the posted code. 编辑 :根据@ShafikYaghmour的评论,include iostream有时会带来string ,但是如果您只有已发布的代码,对于您而言可能并非如此。

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