如何使用cout打印字符串的选定部分

Question

This was a question given to me by my friend who is taking computer programming in college.

Try to write another program using only cout statements to print the initial of your last name in large letters using only *.

cout <<” * “ << endl;
cout <<” * * “ << endl;
cout << 

they use of course though the conio i've never used before.

#include <iostream>
#include <conio.h>
using namespace std;

How would this be possible?

Answer 1

Yes:

// Last name Astari  =>initial of your last name is "A"

std::cout <<  "   **   \n";
std::cout <<  "  *  *  \n";
std::cout <<  "  ****  \n";
std::cout <<  "  ****  \n";
std::cout <<  "  *  *  \n";