[英]Android shell script read
I'm trying to get a shell script to take values. 我正在尝试获取一个shell脚本以获取值。 What I currently have is: 我目前拥有的是:
#!/system/bin/sh
echo "Enter the page numbers"
read page_no_first;
read page_no_final;
#
echo $page_no_first
echo $page_no_final
The echos are simply there for debug, and the problem is that they display as blanks. 回声只是用于调试,而问题在于它们显示为空白。
The terminal results are as such: 最终结果如下:
scriptname
Enter the page numbers
1
1
5
5
Verbatim. 逐字。 That is the echo commands simply produce two empty lines. 也就是说,echo命令仅产生两个空行。
I've found a sort of work around, and another related problem: 我发现了一种解决方法,以及另一个相关问题:
#!/system/bin/sh
echo "Enter the page numbers"
read page_no_first -s
read page_no_final -s
#
echo $page_no_first
echo $page_no_final
This should give me the read without it repeating the input. 这应该给我阅读,而无需重复输入。 Instead, what it gives me is: 相反,它给我的是:
scriptname
Enter the page numbers
1
1
: is readonlyriptname[3]: read: -s
3
3
: is readonlyriptname[3]: read: -s
1
3
Ironically, this successfully writes the numbers to the variables, however, it a) does not give me a silent read, and b) gives me some funny error. 具有讽刺意味的是,这成功地将数字写入了变量,但是,它a)不会给我一个静默读取,b)给了我一些有趣的错误。 Googling it doesn't help, since it's too vague. 谷歌搜索没有帮助,因为它太模糊了。
Any help? 有什么帮助吗?
This work as expected (at least as I think it should): 这项工作符合预期(至少按照我的想法):
#! /system/bin/sh
echo "Enter the page numbers"
echo -n "First: "
read page_no_first
echo -n "Last: "
read page_no_last
echo "First: $page_no_first Last: $page_no_last"
on android 4.2 在Android 4.2上
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