Ruby on Rails：将下拉菜单的选定值传递给函数

Question

I'm using devise and I'm trying to pass the selected value of a drop down menu to a function, but it is not working. The data is being stored in a model called user.

<%= form_for(resource, :as => resource_name, :url => registration_path(resource_name)) do |f| %>
<%= devise_error_messages! %>
<%= f.select :role, options_for_select([["Job Seeker", "candidate"], ["Employer",  "employer"], ["Recruiter", "recruiter"]]) %>

<% if params[:role] == "candidate" %>
<div><%= f.label :travel %><br />
<%= f.text_field :travel %></div> 
<%  end 
if params[:role] == "employer" || params[:role] == "recruiter"
%>
<div><%= f.label :company %><br />
<%= f.text_field :company %></div>
<% end %>
<% end %>

Answer 1

It looks to me as though your conditionals should use the resource object, eg <% if resource.role == "employer" %>

You might want to pass the current value for resource.role as an argument for options_for_select

options_for_select([["Job Seeker", "candidate"], ["Employer",  "employer"], ["Recruiter", "recruiter"]], resource.role)

It seems to me that you want the user to select a role, then display different fields depending on the selected role. Correct me if I'm wrong. From the portion of code which you posted it's impossible to tell exactly what your approach is. There are several ways to solve the problem including:

1. Post the form with the selected role and re-render the form. The process would be similar to re-rendering forms when there is eg a validation error.

2. Break up the form into multiple stages

3. Use javascript to detect when the value of the select has changed and then update the form by showing and hiding fields.