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Sage中的奇怪列表输出

[英]Strange list outputs in Sage

Consider the following two lines of code: 考虑以下两行代码:

For t a dictionary, t = {1: (1, 0, 0, 0, 0, 0, 0, 0, 0), 2: (1, 1, 1, 1, 1, 1, 1, 1, 0)} , when I try to do: list(t[1]) to convert the tuple to a list , it gives me the output [(0,1)] . 对于t字典, t = {1: (1, 0, 0, 0, 0, 0, 0, 0, 0), 2: (1, 1, 1, 1, 1, 1, 1, 1, 0)} ,当我尝试执行以下操作: list(t[1])tuple转换为list ,它给我输出[(0,1)] But when I do list(1,0,0,0) , it gives me (as it should) [1,0,0,0] . 但是当我执行list(1,0,0,0) ,它给了我(应该如此) [1,0,0,0] What is going wrong here? 这是怎么了?

Entire Transcript 整个成绩单

# given a prime p, return all A_n representations of dimension = p^2
def rankrep(p):
    bound = p*p
    s = SymmetricFunctions(QQ).schur()
    Sym_p = s[p]
    A = lambda i: WeylCharacterRing("A{0}".format(i))
    deg = []
    index = []
    L = []
    for i in xrange(bound):
        deg.append([])
        fw = A(i+1).fundamental_weights()
        temp = A(i+1)
        for j in fw.keys():
            deg[i].append(temp(fw[j]).degree())
            if temp(fw[j]).degree() == bound:
                index.append('A'+str(i+1)+'(fw['+str(j)+'])')
                L.append(fw[j])
    return index, deg, L
def make_vars2(L):
    return dict(enumerate(L, start=1))

[index, deg, L] = rankrep(3)
t = make_vars2(L)
print(t[1])
print t
list(t[1])

gives me 给我

(1, 0, 0, 0, 0, 0, 0, 0, 0)
{1: (1, 0, 0, 0, 0, 0, 0, 0, 0), 2: (1, 1, 1, 1, 1, 1, 1, 1, 0)}
[(0, 1)]

Even though your t looks like it's a dictionary with integer keys and tuples of integer values, that's not what it is: 即使您的t看起来像是一本包含整数键和整数值元组的字典,但事实并非如此:

sage: t
{1: (1, 0, 0, 0, 0, 0, 0, 0, 0), 2: (1, 1, 1, 1, 1, 1, 1, 1, 0)}
sage: map(type, t)
[int, int]
sage: map(type, t.values())
[sage.combinat.root_system.ambient_space.AmbientSpace_with_category.element_class,
 sage.combinat.root_system.ambient_space.AmbientSpace_with_category.element_class]
sage: parent(t[1])
Ambient space of the Root system of type ['A', 8]

If you want to get at the vector of coefficients, you can use .to_vector() . 如果要获取系数向量,可以使用.to_vector() For example, we have 例如,我们有

sage: t[1]
(1, 0, 0, 0, 0, 0, 0, 0, 0)
sage: type(t[1])
<class 'sage.combinat.root_system.ambient_space.AmbientSpace_with_category.element_class'>
sage: list(t[1])
[(0, 1)]

but

sage: t[1].to_vector()
(1, 0, 0, 0, 0, 0, 0, 0, 0)
sage: type(t[1].to_vector())
<type 'sage.modules.vector_rational_dense.Vector_rational_dense'>
sage: list(t[1].to_vector())
[1, 0, 0, 0, 0, 0, 0, 0, 0]

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