如何去除字符串中多余的空格？

Question

What function will turn this contains spaces into this contains spaces using javascript?

I've tried the following, using similar SO questions, but could not get this to work.

var string = " this contains   spaces ";

newString = string.replace(/\s+/g,''); // "thiscontainsspaces"
newString = string.replace(/ +/g,'');  //"thiscontainsspaces"

Is there a simple pure javascript way to accomplish this?

Answer 1

You're close.

Remember that replace replaces the found text with the second argument. So:

newString = string.replace(/\s+/g,''); // "thiscontainsspaces"

Finds any number of sequential spaces and removes them. Try replacing them with a single space instead!

newString = string.replace(/\s+/g,' ').trim();

Answer 2

string.replace(/\s+/g, ' ').trim()

Answer 3

Try this one, this will replace 2 or 2+ white spaces from string.

const string = " this contains   spaces ";    
string.replace(/\s{2,}/g, '').trim() 

Answer 4

我想出了一种方法，但很好奇是否有更好的方法......

string.replace(/\s+/g,' ').trim()

Answer 5

I got the same problem and I fixed like this

Text = Text.replace(/ {1,}/g," ");
Text = Text.trim();

Answer 6

I think images always explain it's good, basically what you see that the regex \\s meaning in regex is whitespace. the + says it's can be multiply times. /g symbol that it's looks globally (replace by default looks for the first occur without the /g added). and the trim will remove the last and first whitespaces if exists.

Finally, To remove extra whitespaces you will need this code:

newString = string.replace(/\s+/g,' ').trim();

Answer 7

我们可以使用以下方法删除句子/单词中的多余空格。

sentence.split(' ').filter(word => word).join(' ')

Answer 8

Raw Javascript Solution:

var str = '  k                                     g  alok   deshwal';
function removeMoreThanOneSpace() {
    String.prototype.removeSpaceByLength=function(index, length) {
        console.log("in remove", this.substr(0, index));
        return this.substr(0, index) + this.substr(length);
    }
    for(let i  = 0; i < str.length-1; i++) {
        if(str[i] === " " && str[i+1] === " ") {
            str = str.removeSpaceByLength(i, i+1);
            i = i-1;
        }
    }
    return str;
}
console.log(removeMoreThanOneSpace(str));

Answer 9

var s=" i am a student "
var r='';
console.log(s);
var i,j;
j=0;
for(k=0; s[k]!=undefined; k++);// to calculate the length of a string

for(i=0;i<k;i++){
if(s[i]!==' '){
for(;s[i]!==' ';i++){
r+=s[i];
}
r+=' ';
}
}
console.log(r);

Answer 10

// Here my solution

const trimString = value => {

  const allStringElementsToArray = value.split(''); 
  // transform "abcd efgh" to ['a', 'b', 'c', 'd',' ','e', 'f','g','h']

  const allElementsSanitized = allStringElementsToArray.map(e => e.trim());
  // Remove all blank spaces from array

  const finalValue = allElementsSanitized.join('');
  // Transform the sanitized array ['a','b','c','d','e','f','g','h'] to 'abcdefgh'

  return finalValue;
}

Answer 11

I have tried regex to solve this problem:

let temp=text.replace(/\s{2,}/g, ' ').trim() 
console.log(temp);

input="Plese complete your work on Time"

output="Please complete your work on Time"

Answer 12

//This code remove extra spaces with out using "string objectives" 
      s="                 This Is   Working On      Functions  "
            console.log(s)
            final=""; 
            res='';
        function result(s) {
         for(var i=0;i<s.length;i++)
            {    
                if(!(final==""&&s[i]==" ")&&!(s[i]===" "&& s[i+1] ===" ")){ 
              final+=s[i]; 
               }
            }
           
            console.log(final);
        }
        result(s);