如果在C＃中将具有Int和String类型值的混合的String数组转换为int，如何返回true

Question

I have string which I split to see if any of the split value is string. If so I want to return true else false.

string words = "1 2 c 5";

Easy approach, I can follow by converting into int array and then compare value side by side.

int[] iar = words.Split(' ').Select(s => int.TryParse(s, out n) ? n : 0).ToArray();

Can any one recommend better approach?

Answer 1

You can simply check without using Split :

var result = words.Any(c => !char.IsWhiteSpace(c) 
                         && !char.IsDigit(c));

Or using Split :

var result = words.Split()
                  .Any(w => w.Any(c => !char.IsDigit(c)));

The point is you can use char.IsDigit to check instead of using int.Parse or int.TryParse .

Answer 2

You could do this with a simple little method:

public static bool CheckForNum(string[] wordsArr)
{
     int i = 0;
     foreach (string s in wordsArr)
     {
         if (Int32.TryParse(s, out i))
         {
             return true;
         }
     }
     return false;
 }

Using:

bool result = CheckForNum(words.Split(' '));
Console.Write(result);

Answer 3

Why not use a regular expression? If a string has words and numbers in it, it must have letters and number characters. I don't entirely understand the logic in your question, so you may need to adjust the logic here.

using System;
using System.Text.RegularExpressions;

...

string words = "1 2 c 5";

Match numberMatch = Regex.Match(words, @"[0-9]", RegexOptions.IgnoreCase);
Match letterMatch = Regex.Match(words, @"[a-zA-Z]", RegexOptions.IgnoreCase);

// Here we check the Match instance.
if (numberMatch.Success && letterMatch.Success)
{
    // there are letters and numbers
}