[英]Proper gsub regular expression for this URL?
Say I have a string representing a URL: 假设我有一个表示URL的字符串:
http://www.mysite.com/somepage.aspx?id=33
..I'd like to escape the forward slashes and the question mark: ..我想避免使用正斜杠和问号:
http:\/\/www.mysite.com\/somepage.aspx\?id=33
How can I do this via gsub? 我该如何通过gsub做到这一点? I've been playing with some regular expressions in there but haven't hit on the winning formula yet. 我一直在使用一些正则表达式,但是还没有敲定赢家公式。
I suggest you use 我建议你用
url = url.gsub(/(?=[\/?])/, '\\')
As shown here 如图所示
url = 'http://www.mysite.com/somepage.aspx?id=33'
url = url.gsub(/(?=[\/?])/, '\\')
puts url
output 输出
http:\/\/www.mysite.com\/somepage.aspx\?id=33
这个result = searchText.gsub(/(\\/|\\?)/, "\\\\\\\\$1")
如何result = searchText.gsub(/(\\/|\\?)/, "\\\\\\\\$1")
我建议使用一个块使其更具可读性:
url.gsub(/[\/?]/) { |c| "\\#{c}" }
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