如何从boost :: timer :: cpu_timer获取经过的时间（以秒为单位）？

Question

The following rough code, based on the documentation , gives me the elapsed time in seconds from the timer object provided in boost.

boost::timer::cpu_timer timer;
// ...do some work...
const boost::timer::nanosecond_type oneSecond(1000000000LL);
return timer.elapsed().user / oneSecond;

The problem with this method is that I have this uncomfortable magic number in my code. Is there some method within boost that can give me elapsed seconds out of the nanosecond_type value available from the call to elapsed().user , without having this magic number sitting in my code?

(EDIT:) Conclusion:

Based on the accepted answer, I ended up with this snippet in my production code:

boost::timer::cpu_timer timer;
// ...do some work...
auto nanoseconds = boost::chrono::nanoseconds(timer.elapsed().user + timer.elapsed().system);
auto seconds = boost::chrono::duration_cast<boost::chrono::seconds>(nanoseconds);
std::cout << seconds.count() << std::endl;

Answer 1

As @jogojapan suggested, boost::chrono would be a good choice. But you don't need the duration_cast<> if you use double as underlying type.

typedef boost::chrono::duration<double> sec; // seconds, stored with a double
sec seconds = boost::chrono::nanoseconds(timer.elapsed().user);
std::cout << seconds.count() << "s\n"; // gives the number of seconds, as double.

Answer 2

One more addition:

double
getSeconds( const boost::timer::nanosecond_type& elapsed )
{
  return
    static_cast< double >(
      boost::chrono::nanoseconds( elapsed ).count()
    ) * boost::chrono::nanoseconds::period::num / boost::chrono::nanoseconds::period::den;
}

This you can call with timer.elapsed().user for example to get a double value of the elapsed time. This can obviously also transformed to std::chrono , if wanted / supported.

Answer 3

您应该测量每个硬件运行时每纳秒的滴答数。看看（ 定时器功能使用C ++以纳秒为单位提供时间 ）