[英]XQuery for on items
I know how to use the For instruction to create a loop on a collection or on a document but I have troubles to create a loop on an item()* 我知道如何使用For指令在集合或文档上创建循环,但我在项目上创建循环有麻烦()*
content of item()*: item()*的内容:
<Placemark>
<blabla id="1">
<value>abcd</value>
</blabla>
<blabla id="2">
<value>abcd</value>
</blabla>
...
</Placemark>
<Placemark>
...
</Placemark>
Now I need for example the <blabla>
elements only. 现在我只需要
<blabla>
元素。 With a classic loop on a document, I access like this : 通过文档上的经典循环,我可以这样访问:
for $x in doc("/db/data.xml")/Placemark
return $x
but with a loop on a item()*, it doesn't work like this : 但是在item()*上有一个循环,它不能像这样工作:
declare function local:fct($content as item()*) as item()* {
for $x in $content/Placemark
return $x
};
I have no error, just a blank result. 我没有错误,只是一个空白的结果。 Someone know why it doesn't work?
有人知道它为什么不起作用?
Because your loop is already iterating over Placemark
items, your solution asks for Placemark
children of Placemark
, which is empty. 因为你的循环已经结束迭代
Placemark
项目,您的解决方案询问Placemark
儿童的Placemark
,里面是空的。
declare function local:fct(
$content as element(Placemark)*
) as element(blabla)* {
for $x in $content
return $x/blabla
};
If you were passing the parent of the Placemark elements to the function as the value of the $content parameter, your code would be fine. 如果您将Placemark元素的父元素作为$ content参数的值传递给函数,那么您的代码就可以了。 But it looks as if you're calling the function with some expression like
local:fct(doc(...)//Placemark)
, which means the members of the $content sequence are themselves the Placemark elements. 但看起来好像你用一些像
local:fct(doc(...)//Placemark)
这样的表达式来调用函数local:fct(doc(...)//Placemark)
,这意味着$ content序列的成员本身就是Placemark元素。 Your function then asks for their Placemark children; 然后你的功能要求他们的地标儿童; there are none, so the empty sequence is what you get.
没有,所以空序列就是你得到的。
The revised function suggested by wst is a fine way to fix the problem; wst建议的修订功能是解决问题的好方法; passing in the parents of the Placemark elements as the value of $content would be another fine way.
传递地标元素的父母作为$ content的价值将是另一种好方法。
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