[英]python : reading a datetime from a log file using regex
I have a log file which has text that looks like this. 我有一个日志文件,其文本看起来像这样。
Jul 1 03:27:12 syslog: [m_java][ 1/Jul/2013 03:27:12.818][j:[SessionThread <]^Iat com/avc/abc/magr/service/find.something(abc/1235/locator/abc;Ljava/lang/String;)Labc/abc/abcd/abcd;(bytecode:7)
There are two time formats in the file. 文件中有两种时间格式。 I need to sort this log file based on the date time format enclosed in []. 我需要根据[]中包含的日期时间格式对此日志文件进行排序。
This is the regex I am trying to use. 这是我试图使用的正则表达式。 But it does not return anything. 但它不会返回任何东西。
t_pat = re.compile(r".*\[\d+/\D+/.*\]")
I want to go over each line in file, be able to apply this pattern and sort the lines based on the date & time. 我想遍历文件中的每一行,能够应用此模式并根据日期和时间对行进行排序。
Can someone help me on this? 有人可以帮我吗? Thanks! 谢谢!
You have a space in there that needs to be added to the regular expression 你有一个空间需要添加到正则表达式
text = "Jul 1 03:27:12 syslog: [m_java][ 1/Jul/2013 03:27:12.818][j:[SessionThread <]^Iat com/avc/abc/magr/service/find.something(abc/1235/locator/abc;Ljava/lang/String;)Labc/abc/abcd/abcd;(bytecode:7)"
matches = re.findall(r"\[\s*(\d+/\D+/.*?)\]", text)
print matches
['1/Jul/2013 03:27:12.818']
Next parse the time using the following function 接下来使用以下函数解析时间
http://docs.python.org/2/library/time.html#time.strptime http://docs.python.org/2/library/time.html#time.strptime
Finally use this as a key into a dict, and the line as the value, and sort these entries based on the key. 最后使用它作为dict的键,并将行作为值,并根据键对这些条目进行排序。
You are not matching the initial space; 你不匹配初始空间; you also want to group the date for easy extraction, and limit the \\D
and .*
patterns to non-greedy: 您还希望将日期分组以便于提取,并将\\D
和.*
模式限制为非贪婪:
t_pat = re.compile(r".*\[\s?(\d+/\D+?/.*?)\]")
Demo: 演示:
>>> re.compile(r".*\[\s?(\d+/\D+?/.*?)\]").search(line).group(1)
'1/Jul/2013 03:27:12.818'
You can narrow down the pattern some more; 你可以更多地缩小模式; you only need to match 3 letters for the month for example: 你只需要匹配月份的3个字母,例如:
t_pat = re.compile(r".*\[\s?(\d{1,2}/[A-Z][a-z]{2}/\d{4} \d{2}:\d{2}:[\d.]{2,})\]")
Read all the lines of the file and use the sort
function and pass in a function that parses out the date and uses that as the key for sorting : 读取文件的所有行并使用sort
函数并传入一个解析日期并将其用作排序键的函数:
import re
import datetime
def parse_date_from_log_line(line):
t_pat = re.compile(r".*\[\s?(\d+/\D+?/.*?)\]")
date_string = t_pat.search(line).group(1)
format = '%d/%b/%Y %H:%M:%S.%f'
return datetime.datetime.strptime(date_string, format)
log_path = 'mylog.txt'
with open(log_path) as log_file:
lines = log_file.readlines()
lines.sort(key=parse_date_from_log_line)
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