[英]Does Python have a function to reduce fractions?
For example, when I calculate 98/42
I want to get 7/3
, not 2.3333333
, is there a function for that using Python or Numpy
?例如,当我计算
98/42
时,我想得到7/3
而不是2.3333333
,是否有 function 用于使用 Python 或Numpy
?
The fractions
module can do that fractions
模块可以做到这一点
>>> from fractions import Fraction
>>> Fraction(98, 42)
Fraction(7, 3)
There's a recipe overhere for a numpy gcd. 这里有一个 numpy gcd 的配方。 Which you could then use to divide your fraction
然后你可以用它来划分你的分数
>>> def numpy_gcd(a, b):
... a, b = np.broadcast_arrays(a, b)
... a = a.copy()
... b = b.copy()
... pos = np.nonzero(b)[0]
... while len(pos) > 0:
... b2 = b[pos]
... a[pos], b[pos] = b2, a[pos] % b2
... pos = pos[b[pos]!=0]
... return a
...
>>> numpy_gcd(np.array([98]), np.array([42]))
array([14])
>>> 98/14, 42/14
(7, 3)
Addition to John's answer:除了约翰的回答:
To get simplified fraction from a decimal number (say 2.0372856077554062)从十进制数中得到简化分数(比如 2.0372856077554062)
Using Fraction gives the following output:使用 Fraction 给出以下输出:
Fraction(2.0372856077554062)
#> Fraction(4587559351967261, 2251799813685248)
To get simplified answer :要获得简化的答案:
Fraction(2.0372856077554062).limit_denominator()
#> Fraction(2732, 1341)
This python code uses only the math module """此 python 代码仅使用数学模块“””
import math
def _fractions_(numerator, denominator):
if math.gcd(numerator, denominator) == denominator:
return int(numerator/denominator)
elif math.gcd(numerator, denominator) == 1:
return str(numerator) + "/" + str(denominator)
else:
top = numerator / math.gcd(numerator, denominator)
bottom = denominator / math.gcd(numerator, denominator)
return str(top) + "/" + str(bottom)
print(_fractions_(46,23))
print(_fractions_(34,25))
print(_fractions_(24, 28))
""" """
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