MIPS将整数转换为float

Question

I'm really new in MIPS assembly and I am wondering can I do something like:

Not just three characters number, any length of X and Y

Please help If you know the algorithm or where can I find the code or algorithm

(Sorry I thought image might describe better and faster)

Thank you ...

Answer 1

Consider the following pseudo-code:

int x = input
int y = input

while y > 1:
    y = y / 10

return x + y

Of course you will have to be cognizant of the normal floating point precision sticking points, ie that this can only at best get you as close as possible to XXX.YYY given the representation.