MIPS将浮点数转换为整数

Question

I've tried looking at it a couple different ways, one of them was using binary to shift left/right but I just wasn't able to find a combination to make it work for anything besides a few selected numbers each time. So how do you convert a float into an integer?

.data
five: .float 10.0

.text

main:
    la  $a1 five 
    l.s $f12 ($a1) 
    #conversion here

    li $v0 2# print float, which will print 10.0 (should print integer)
    syscall

    li $v0 10
    syscall

Answer 1

Disclaimer : I'm not an expert on MIPS arch.

As suggested in the comments, a quick lookup for MIPS FP reference gives the desired instruction: cvt.ws .

.data
    five: .float 5.0
.text

#Convert five into an integer
la $t1, five
l.s $f12, ($t1)             #f12 = five
cvt.w.s $f0, $f12           #f0 = (int) five


#Print five
li $v0, 2
syscall

#Print (int)five
li $v0, 1
mfc1 $a0, $f0               #a0 = (int)five
syscall

#Exit
li $v0, 10
syscall

This will print

5.05

As there is no space between the 5.0 and the 5 .

If you want to do it by hand, you can start from this answer .