[英]deal with many members datas from mysql with php
I have an array and the createtime is already sorted by AES. 我有一个数组,并且创建时间已按AES排序。
$list = array(0 => array('createtime' => 90,'message'=>'ad','user'=>'a'),
1 => array('createtime' => 91,'message'=>'ae','user'=>'b'),
2 => array('createtime' => 93,'message'=>'ae','user'=>'b'),
3 => array('createtime' => 93,'message'=>'ae','user'=>'c'),
4 => array('createtime' => 94,'message'=>'ah','user'=>'d'),
5 => array('createtime' => 99,'message'=>'ah','user'=>'a'),
6 => array('createtime' => 100,'message'=>'ah','user'=>'a'));
As you can see,maybe the array is from a sql table,what I want is to deal with these data,the result of array like this.
$list = array(0 => array('createtime' => 90,'message'=>'ad','user'=>'a'),
1 => array('createtime' => 91,'message'=>'ae+ae','user'=>'b'),
2 => array('createtime' => 93,'message'=>'ae','user'=>'c'),
3 => array('createtime' => 94,'message'=>'ah','user'=>'d'),
4 => array('createtime' => 99,'message'=>'ah+ah','user'=>'a'));
Yeah, you may find the createtime between 5 and the same user data combined.What I want is just like this,and in the future it may includes more users and more createtimes. 是的,您可能会发现创建时间介于5和相同的用户数据之间。我想要的就是这样,将来可能包含更多的用户和更多的创建时间。 And I coded like this to deal with it,but it worked not well when I change my datas like add user or change user and so on.
而且我像这样编码来处理它,但是当我更改数据(例如添加用户或更改用户等)时,它不能很好地工作。
$diff = 0;
$count = 0;
$d = array();
$j = array();
for($i = 1;isset($list[$i]);){
if ($list[$i]['user'] != $list[$i-1-$count]['user']) {
if (!in_array($list[$i]['user'], $d)) {
$d[$diff] = $list[$i]['user'];
$j[$diff] = $i;
$count++;
$diff++;
$i++;
continue;
} else {
$i++;
$count++;
continue;
}
}
if($list[$i]['createtime'] - $list[$i-1-$count]['createtime'] < 5){
$list[$i-1-$count]['message'] = $list[$i-1-$count]['message'].'<br>'.$list[$i]['message'];
array_splice($list,$i,1);
} else if ($count == 0) {
$i++;
} else {
$i = $j[0] + 1;
$count = 0;
$diff = 0;
$d = array();
$j = array();
}
}
It seems to have something wrong.So how should I do to meet my requirements.And more users between short createtime should also be considered.Thanks. 似乎有问题,所以我应该怎么做才能满足我的要求,并且还应该考虑在较短的创建时间之间增加用户数量。
So, you're after something like this? 所以,你在追求这样的事情吗?
$list = array(0 => array('createtime' => 90,'message'=>'ad','user'=>'a'),
1 => array('createtime' => 91,'message'=>'ae','user'=>'b'),
2 => array('createtime' => 93,'message'=>'ae','user'=>'b'),
3 => array('createtime' => 93,'message'=>'ae','user'=>'c'),
4 => array('createtime' => 94,'message'=>'ah','user'=>'d'),
5 => array('createtime' => 99,'message'=>'ah','user'=>'a'),
6 => array('createtime' => 100,'message'=>'ah','user'=>'a'));
$out = array();
$prevUser = 0;
foreach($list as $key => $value){
if($value['user'] === $prevUser){
echo $value['user'], $prevUser, '<br>';
end($out);
$k = key($out);
$out[$k]['message'] .= $value['message'];
continue;
}
$out[] = $value;
$prevUser = $value['user'];
}
echo '<pre>';
print_r($out);
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