通过将属性的名称传递给方法来获取属性的名称

Question

StackOverflow user jolson had a very nice piece of code that exemplifies how one can register menthods without using strings, but expression trees here .

Is it possible to have something similar for properties instead of methods? To pass a property (not the name of the property) and inside the method to obtain the property name?

Something like this:

    RegisterMethod(p => p.Name)

    void RegisterMethod(Expression??? propertyExpression) where T : Property ???
    {
        string propName = propertyExpression.Name;
    }

Thanks.

Answer 1

I posted a full example of this here (see also the post about " this " underneath it)

Note it deals with the LambdaExpression etc. As an update to the code as posted, you can add a bit more to make it easier to use in some scenarios:

static class MemberUtil<TType>
{
    public static string MemberName<TResult>(Expression<Func<TType, TResult>> member)
    {
        return MemberUtil.MemberName<TType, TResult>(member);
    }
}

Then you can use generic type-inference for the return value:

string test1 = MemberUtil<Foo>.MemberName(x => x.Bar); 
string test2 = MemberUtil<Foo>.MemberName(x => x.Bloop()); 

Answer 2

You can write something along this:

static void RegisterMethod<TSelf, TProp> (Expression<Func<TSelf, TProp>> expression)
{
    var member_expression = expression.Body as MemberExpression;
    if (member_expression == null)
        return;

    var member = member_expression.Member;
    if (member.MemberType != MemberTypes.Property)
        return;

    var property = member as PropertyInfo;
    var name = property.Name;

    // ...
}