如何从字符串中删除除数字、“,”和“.”之外的所有字符使用红宝石？

Question

Please, help me with a regexp for the next task: I have a 'cost' column in some table, but the values there are different:

['1.22','1,22','$1.22','1,22$','$ 1.22']

I need to remove every character except digits and , and . . So I need to get a value that always can be parsed as Float.

Answer 1

a.map {|i| i.gsub(/[^\d,\.]/, '')}
# => ["1.22", "1,22", "1.22", "1,22", "1.22"] 

Answer 2

Try this:

yourStr.gsub(/[^0-9,.]/, "")

Answer 3

To extract the numbers:

a = ["1.22", "1,22", "$1.22", "1,22$", "$ 1.22"]
a.map {|s| s[/[\d.,]+/] }
#=> ["1.22", "1,22", "1.22", "1,22", "1.22"]

Assuming commas , should be treated like decimal points . (as in '1,22' -> 1.22 ), this should convert your values to float:

a = ["1.22", "1,22", "$1.22", "1,22$", "$ 1.22"]
a.map {|s| s[/[\d.,]+/].gsub(',','.').to_f }
#=> [1.22, 1.22, 1.22, 1.22, 1.22]

Answer 4

you can replace all white space, all '$' by ''

Answer 5

Another one:

a= ['1.22','1,22','$1.22','1,22$','$ 1.22']
a.map{|i| i[/\d+.\d+/]}
# => ["1.22", "1,22", "1.22", "1,22", "1.22"]

Answer 6

str = "a1234c324ee4r"    
str.delete("^0-9")

It deletes all the characters from string and return all the integers

Answer 7

Please, help me with a regexp for the next task: I have a 'cost' column in some table, but the values there are different:

['1.22','1,22','$1.22','1,22$','$ 1.22']

I need to remove every character except digits and , and . . So I need to get a value that always can be parsed as Float.