Ruby-从字符串中删除所有其他字符

Question

I have a string h2#test- ruby is so awesome, blah, blah, blah . I want to have #test to be the only characters left. is there a way in ruby to run a Regular Expression that removes all other characters?

Answer 1

str.match(/(\#\w+)/)[1]

Answer 2

Don't think of it as removing all other characters...think of it as capturing what you want.

'h2#test- ruby is so awesome, blah, blah, blah' =~ /(#test)/
your_captured_text = $1

Answer 3

str[/#[a-z]+/i]