[英]How to sort this lua table?
I have next structure 我有下一个结构
self.modules = {
["Announcements"] = {
priority = 0,
-- Tons of other attributes
},
["Healthbar"] = {
priority = 40,
-- Tons of other attributes
},
["Powerbar"] = {
priority = 35,
-- Tons of other attributes
},
}
I need to sort this table by priorty DESC, other values does not matter. 我需要通过priorty DESC对此表进行排序,其他值无关紧要。 Eg Healthbar first, then Powerbar, and then going all others.
例如Healthbar,然后是Powerbar,然后去其他所有人。
// edit. //编辑
Keys must be preserved. 必须保留密钥。
// edit #2 //编辑#2
Found a solution, thanks you all. 找到了解决方案,谢谢大家。
local function pairsByPriority(t)
local registry = {}
for k, v in pairs(t) do
tinsert(registry, {k, v.priority})
end
tsort(registry, function(a, b) return a[2] > b[2] end)
local i = 0
local iter = function()
i = i + 1
if (registry[i] ~= nil) then
return registry[i][1], t[registry[i][1]]
end
return nil
end
return iter
end
You can't sort a records table because entries are ordered internally by Lua and you can't change the order. 您无法对记录表进行排序,因为Lua在内部对条目进行排序,您无法更改顺序。
An alternative is to create an array where each entry is a table containing two fields ( name and priority ) and sort that table instead something like this: 另一种方法是创建一个数组,其中每个条目都是一个包含两个字段( 名称和优先级 )的表,并对该表进行排序,而不是这样:
self.modulesArray = {}
for k,v in pairs(self.modules) do
v.name = k --Store the key in an entry called "name"
table.insert(self.modulesArray, v)
end
table.sort(self.modulesArray, function(a,b) return a.priority > b.priority end)
for k,v in ipairs(self.modulesArray) do
print (k,v.name)
end
Output: 输出:
1 Healthbar 40
2 Powerbar 35
3 Announcements 0
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