[英]mysql query (multiple counts)
With this query: 使用此查询:
SELECT abc, def, COUNT(*) as c
FROM xpto
GROUP BY abc, def
ORDER BY abc, c DESC
I have this result: 我有这个结果:
xpto
abc | def | c
x | c_1 | 8
...
y | a_2 | 4
y | a_1 | 2
y | a_3 | 1
…
z | b_2 | 7
z | b_1 | 3
...
I wish to have this result (ordered by number of entries for each abc and field c): 我希望得到这个结果(按每个abc和字段c的条目数排序):
y | a_2
y | a_1
y | a_3
z | b_2
z | b_1
x | c_1
Can a SQL guru help me with this task? SQL专家可以帮助我完成此任务吗? I've seen this example SQL Help: Counting Rows in a Single Query With a Nested SELECT , is this a good solution (nested select), or there is no other way to do? 我已经看过这个示例SQL帮助:使用嵌套SELECT的单个查询中的行计数 ,这是一个好的解决方案(嵌套选择),还是没有其他方法可做?
Thanks in advance 提前致谢
Use a nested query: 使用嵌套查询:
SELECT abc, def
FROM (
SELECT abc, def, COUNT(*) as c
FROM xpto
GROUP BY abc, def
) alias
ORDER BY abc, c DESC
(from comment) The challenge is not order abc alphabetically but by number of entries with the same value. (来自注释)挑战不是按字母abc顺序排序,而是按具有相同值的条目数排序。 I edited the example in question to better understand the ultimate goal. 我编辑了相关示例,以更好地理解最终目标。
OK, then just change the order of columns in the ORDER BY clause: OK,然后只需更改ORDER BY子句中的列顺序即可:
SELECT abc, def, c
FROM (
SELECT abc, def, COUNT(*) as c
FROM xpto
GROUP BY abc, def
) alias
ORDER BY c DESC, abc;
The above query gives aggregate valuse (ie Unique rows - one row per each pair of values). 上面的查询给出了合计值(即唯一行-每对值一对)。
If you wish to list all rows from the table ordered by number of entries, try this query: 如果您希望列出表中按条目数排序的所有行,请尝试以下查询:
SELECT abc, def,
( SELECT COUNT(*) FROM xpto x1
WHERE ( x.abc, x.def ) = (x1.abc, x1.def)
) as c
FROM xpto x
ORDER by c desc, abc
;
This query displays columns abc, def + count. 该查询显示abc,def + count列。 If you want to display only abc + def, without the value of count, then try this query: 如果只想显示abc + def,而没有count的值,请尝试以下查询:
SELECT abc, def
FROM xpto x
ORDER by ( SELECT COUNT(*) FROM xpto x1
WHERE x.abc = x1.abc AND x.def = x1.def
) desc,
abc
;
Look at sqlfiddle demo that demonstrates these 3 queries. 看一下展示这3个查询的sqlfiddle演示 。
Pay attention to the condition used in the second query (in the dependent subquery): 请注意第二个查询(从属子查询)中使用的条件:
WHERE ( x.abc, x.def ) = (x1.abc, x1.def)
This syntax is complaint with ANSI SQL, however may not work on some older version of MySQL. ANSI SQL抱怨这种语法,但是可能不适用于某些旧版本的MySQL。 In that case, change this condition to its equivalent version: 在这种情况下,请将此条件更改为等效版本:
WHERE x.abc = x1.abc AND x.def = x1.def
Check this query 检查此查询
SELECT abc, def, COUNT(*) as c,
(SELECT COUNT(1) FROM (
SELECT abc, def, COUNT(*) as c
FROM xpto A
GROUP BY abc, def
) B
GROUP BY ABC
HAVING C.abc=B.abc
) ic
FROM xpto C
GROUP BY abc, def
ORDER BY ic DESC, c DESC
This may not be the best way to achieve this, but it works (Check this SQL Fiddle ) 这可能不是实现此目的的最佳方法,但它可以工作(请检查此SQL Fiddle )
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