[英]MYSQL - Multiple counts in a single query
I'm trying to do multiple counts in a single query but still not getting the results I want. 我正在尝试在单个查询中进行多次计数,但仍然没有得到想要的结果。 There are 6 servers on 5F / 6F and I want to count how many servers on 5F / 6F are using CPU more than 50% or how many servers on 5F / 6F are using CPU less than 50%. 5F / 6F上有6台服务器,我想计算5F / 6F上有多少服务器使用的CPU超过50%,或者5F / 6F上有多少服务器使用的CPU少于50%。
I tried to send the below query but the result is not separated by group. 我尝试发送以下查询,但结果未按组分开。
SELECT room, (SELECT count( > 50) FROM table WHERE empty > 50),
(SELECT count( < 50) FROM table WHERE empty < 50) FROM table GROUP BY location;
Table: 表:
| name | location | CPU usage |
| host1 | 5F | 60 |
| host2 | 5F | 20 |
| host2 | 5F | 80 |
| host3 | 6F | 30 |
| host4 | 6F | 40 |
| host5 | 6F | 90 |
Desired output: 所需的输出:
| location | > 50 | < 50 |
| 5F | 2 | 1 |
| 6F | 1 | 2 |
Could you try this? 你可以试试这个吗?
SELECT location, SUM(IF(cpu_usage > 50, 1, 0)), SUM(IF(cpu_usage <=50, 0, 1))
FROM table
GROUP BY location
As ScayTrase mentioned, cpu_usage > 50
itselfs return 0 or 1 for true or false respectively. 正如ScayTrase所述, cpu_usage > 50
本身分别返回0或1(表示true或false)。 So, preceding query could be simplified as follows. 因此,先前的查询可以简化如下。
SELECT location, SUM(cpu_usage > 50), SUM(cpu_usage <=50)
FROM table
GROUP BY location
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