合并，洗牌和获取列表的前n个元素的更短方法

Question

I'm doing that (see code) and i'm thinking that there will be a shorter way

    fd_list = list(set(fd_list1 + fd_list2 + fd_list3))
    shuffle(fd_list)
    fd_list = fd_list[:10]

what i want to do is: concatenate three list's, shuffle them and take the first 10 elements. Alternativ i could merge the three list's and take randomly 10 elements?!Maybe?! I don't know how. By the way the result list have to be unique.

EDIT*: example list1 = [ 1, 2, 3, 6], list2 = [], list3 = [4, 5, 6, 6, 7, 8, ,8]

a result should maybe look like this...

result = [3, 4, 5, 1 ,8 ,2 ,7 ,6] 

i think the "sample" solution would be the best. Thanks a lot!

Answer 1

random.sample(set(fd_list1 + fd_list2 + fd_list3), 10)