Python，PySide睡眠没有拖延整个程序？

Question

I have this piece of code:

 self.connect(self.Yes_button,SIGNAL('clicked()'),self.Yes_pressed)
 self.connect(self.No_button,SIGNAL('clicked()'),self.No_pressed)

def Yes_pressed(self):
    self.Box.append("Hello")
    time.sleep(2)
    self.Box.append("Text2")

what it does is when the Yes button is pressed it waits 2 seconds first then appends both Hello and Text2(Box is a QTextBrowser() object)How could I make so it would appending one, wait 2 seconds and append the other one instead? Is there a simple solution to this?

Answer 1

You can do something like this, using pyqt's Qtimer . More specifically the singleShot

Setup : QTimer.singleShot (int msec, QObject receiver, SLOT()SLOT() member)

QtCore.QTimer.singleShot(1000, lambda: self.Box.append("Text2")) #1000 milliseconds = 1 second

Or you can event try this implementation:

    self.timerScreen = QTimer()
    self.timerScreen.setInterval(1000) #1000 milliseconds = 1 second
    self.timerScreen.setSingleShot(True)
    self.timerScreen.timeout.connect(self.Box.append("Text2"))

You can probably do something like this, but I do not recommend it:

def testSleep(self):
    self.lineEdit.setText('Start')
    QtCore.QTimer.singleShot(10000, lambda: self.Box.append("Text2")) 
    QtCore.QTimer.singleShot(10000,lambda: self.timerEvent)


def timerEvent(self):
    QtCore.QTimer.singleShot(10000, lambda: self.Box.append("Text3"))

You are better off just doing something like this:

x = 10000 #or whatever number
QtCore.QTimer.singleShot(10000 + x, lambda: self.Box.append("Text3"))