如何提取xml列的元素？

Question

How do I extract the elements to xml column?

<V>
  <r>
    <ID>alkj</ID>
    <Date>2013-01-02T00:00:00-02:00</Date>
    <Value>97429.91</Value>
  </r>
  <r>
    <ID>asdf</ID>
    <Date>2014-01-02T00:00:00-02:00</Date>
    <Value>90121.18</Value>
  </r>
<V>

need only what is inside the element v, the return needs to be:

<r>
    <ID>alkj</ID>
    <Date>2013-01-02T00:00:00-02:00</Date>
    <Value>97429.91</Value>
  </r>
  <r>
    <ID>asdf</ID>
    <Date>2014-01-02T00:00:00-02:00</Date>
    <Value>90121.18</Value>
</r>

but I can not use

select colunaxml.query('(/v/r)') from tabela

because V is not always V ! but the internal elements are always r

thank for help!

Answer 1

SELECT colunaxml.query('(/*/r)')

如果您已经知道父元素名称始终是<v> ， <a> ， <b>或<c> ，则在指定它们时XPath的执行速度可能会更快：

SELECT colunaxml.query('(/(v | a | b | c)/r)')