[英]How to choose a attributes from XML using the XSLT?
<students>
<student student-name="Leo">
<program> BIT </program>
<study-model> on-campus </study-model>
</student>
<student student-name="Dan">
<program> MIT </program>
<study-model> off-campus </study-model>
</student>
</students>
can anyone help me ? 谁能帮我 ? im still a newbie for XML - XSLT .. i was trying to develop the XSTL for the XML data above
我仍然是XML-XSLT的新手。。我正在尝试为上述XML数据开发XSTL。
like i just want to choose the student name Dan , including his Program and study model for the output of the XML .. 就像我只想选择学生姓名Dan一样,包括XML和XML输出的程序和学习模型。
what code should i use to choose the attributes from the XML ? 我应该使用什么代码从XML中选择属性?
the example of the output will be like this: 输出示例如下:
just a bit difference with the data (using student name not student number , etc) 与数据略有不同(使用学生姓名而不是学生编号等)
You can do something like the following: 您可以执行以下操作:
<?xml version="1.0" ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" encoding="utf-8" indent="yes" />
<xsl:template match="students">
<table>
<xsl:apply-templates select="student" />
</table>
</xsl:template>
<xsl:template match="student">
<tr>
<td>
Student Name: <xsl:value-of select="@student-name" />
</td>
<xsl:apply-templates />
</tr>
</xsl:template>
<xsl:template match="*">
<td>
<xsl:value-of select="name(.)" />: <xsl:value-of select="." />
</td>
</xsl:template>
</xsl:stylesheet>
This will output: 这将输出:
<table>
<tr>
<td>
Student Name: Leo</td>
<td>program: BIT </td>
<td>study-model: on-campus </td>
</tr>
<tr>
<td>
Student Name: Dan</td>
<td>program: MIT </td>
<td>study-model: off-campus </td>
</tr>
</table>
You can style this table by adding classes to the td in xsl, then adding css. 您可以通过在xsl中将类添加到td中,然后添加css来设置此表的样式。
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