[英]Is there an easy way to read file contents in array format in PHP?
I am trying to make use of files(.txt) to print logs. 我正在尝试使用文件(.txt)来打印日志。 Inside the file, it logs an array value which looks like this:
在文件内部,它记录一个如下所示的数组值:
Array
(
[NAME] => John Peters
[AGE] => 24
[COUNTRY] => United States
[EMAIL] => test@test.com
)
So now, I am trying to read the file contents and covert it onto an actual array so that I would be able to reference the value using the array key in a php file, something like: 所以现在,我正在尝试读取文件内容并将其转换为实际数组,以便我能够使用php文件中的数组键引用该值,例如:
echo 'Name : ' .$person['NAME'];
echo 'Age: ' .$person['AGE'];
echo 'Country: ' .$person['COUNTRY'];
echo 'Email: ' .$person['EMAIL'];
Is there a predefined php function to do it? 是否有预定义的PHP函数来做到这一点? Or how will I be able to accomplish what I want.
或者我将如何实现我想要的目标。 I have tried to use the fread() and fgets() function but it doesn't really accomplish what I want or I might be missing something.
我曾尝试使用fread()和fgets()函数,但它并没有真正实现我想要的东西,或者我可能会遗漏一些东西。
I wrote a quick script for you, I assumed that in your (files).txt can contain many entries of print_r
results eg 我为你写了一个快速脚本,我假设你的(文件).txt可以包含许多
print_r
结果条目,例如
Array
(
[NAME] => John Peters
[AGE] => 24
[COUNTRY] => United States
[EMAIL] => test@test.com
)
Array
(
[NAME] => John Peters
[AGE] => 24
[COUNTRY] => United States
[EMAIL] => test@test.com
)
This script assumes that your inputs test.txt
only contains array that has 1 level (so, it won't work with nested array) 此脚本假定您的输入
test.txt
仅包含具有1级别的数组(因此,它不适用于嵌套数组)
$c = file_get_contents('test.txt');
# Matches all strings that has 'Array(...)' pattern
preg_match_all('#Array[^\)]+\)#', $c, $matches);
$items = array();
foreach($matches[0] as $match) {
# Extracts KEY => VAL patterns from matched text
if (preg_match_all('#\[([^\]]+)\].*?>(.*)#', $match, $array)) {
$items[] = array_combine($array[1], $array[2]);
}
}
# test your results
print_r($items);
you can read it using file_get_contents 你可以使用file_get_contents来阅读它
Eg: 例如:
<?php
$homepage = file_get_contents('abc.txt');
echo $homepage;
?>
Hope it will help :) 希望它会有所帮助:)
I guess @Rezigned and I had the same idea... Here's what I came up with: 我想@Rezigned和我有同样的想法......这就是我想出的:
<?php
$file = file_get_contents('log.txt');
$file = preg_match_all('/(\s+\[[a-zA-Z0-9]+\]\s+=>\s+.+)\n/', $file, $lines);
$key = array();
$val = array();
foreach ($lines[0] as $line) {
$keys_vals = preg_split('/(\s+=>\s+)/', $line);
$key[] .= preg_replace('/[\[|\]]/', '', $keys_vals[0]);
$val[] .= $keys_vals[1];
}
$line_count = count($lines[0]);
for ($i = 0; $i < $line_count; $i++) {
print $key[$i] . ': ' . $val[$i];
}
There is a function shared by Matt in PHP manual called print_r_reverse
, I think it's what you want. Matt在PHP手册中分享了一个名为
print_r_reverse
,我认为这就是你想要的。 The following code is copied from PHP manual print_r
function comments section directly. 以下代码直接从PHP手册
print_r
函数注释部分复制。
<?php
function print_r_reverse($in) {
$lines = explode("\n", trim($in));
if (trim($lines[0]) != 'Array') {
// bottomed out to something that isn't an array
return $in;
} else {
// this is an array, lets parse it
if (preg_match("/(\s{5,})\(/", $lines[1], $match)) {
// this is a tested array/recursive call to this function
// take a set of spaces off the beginning
$spaces = $match[1];
$spaces_length = strlen($spaces);
$lines_total = count($lines);
for ($i = 0; $i < $lines_total; $i++) {
if (substr($lines[$i], 0, $spaces_length) == $spaces) {
$lines[$i] = substr($lines[$i], $spaces_length);
}
}
}
array_shift($lines); // Array
array_shift($lines); // (
array_pop($lines); // )
$in = implode("\n", $lines);
// make sure we only match stuff with 4 preceding spaces (stuff for this array and not a nested one)
preg_match_all("/^\s{4}\[(.+?)\] \=\> /m", $in, $matches, PREG_OFFSET_CAPTURE | PREG_SET_ORDER);
$pos = array();
$previous_key = '';
$in_length = strlen($in);
// store the following in $pos:
// array with key = key of the parsed array's item
// value = array(start position in $in, $end position in $in)
foreach ($matches as $match) {
$key = $match[1][0];
$start = $match[0][1] + strlen($match[0][0]);
$pos[$key] = array($start, $in_length);
if ($previous_key != '') $pos[$previous_key][1] = $match[0][1] - 1;
$previous_key = $key;
}
$ret = array();
foreach ($pos as $key => $where) {
// recursively see if the parsed out value is an array too
$ret[$key] = print_r_reverse(substr($in, $where[0], $where[1] - $where[0]));
}
return $ret;
}
}
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