回显查询结果的每条记录

Question

I'm attempting to extract some data from a database and echo each result. The code below is code that I took from a textbook and then tried to modify to fit my own website that is hosted locally. I cannot see where I'm going wrong, no error messages are shown, just a blank screen when I run the scrip.

<?php #script 9.4 view top 5 recipients
// This script exctracts data from db and then displays each record in a table

    DEFINE('SYSPATH','FOO');

    require '../application/config/database.php';

    require 'mysqli_connect.php';

    $q = "SELECT alert_recipient as NAME
          FROM alert
          LIMIT 5;
          ";

    $r = mysqli_query($dbc,$q);

    // $dbc database connection comes from required mysqli_connect.php       

    if($r) 
        {

        while($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) {

            echo $row['name'];
        }

        }


    else {
        echo "<p>ERROR</p>".mysqli_error($dbc);
        }

?>

Answer 1

The code looks okay except for your echo $row['name']; , note that you are selecting NAME , uppercase.

Change your echo statement to be:

echo $row['NAME'];

because field names quoted within $row array are case sensitive.

Answer 2

(Can't comment yet)

Maybe the script works but there is no results to display. Check your database.